What is (ln(15)-ln(2))/(ln(1.05)-ln(1.19)) ?

The solution to (ln(15)-ln(2))/(ln(1.05)-ln(1.19)) is (ln(15/2))/(ln(0.88235…))

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simplify (ln(15)-ln(2))/(ln(1.05)-ln(1.19))

simplify

\frac{ln ( 15 ) - ln ( 2 )}{ln ( 1.05 ) - ln ( 1.19 )}

\frac{ln ( \frac{15}{2} )}{ln ( 0.88235 \dots )}

Decimal Notation

- 16.09821 \dots

Solution steps

\frac{ln ( 15 ) - ln ( 2 )}{ln ( 1.05 ) - ln ( 1.19 )}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (15) - ln (2) = ln (\frac{15}{2})

= \frac{ln ( \frac{15}{2} )}{ln ( 1.05 ) - ln ( 1.19 )}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (1.05) - ln (1.19) = ln (\frac{1.05}{1.19})

= \frac{ln ( \frac{15}{2} )}{ln ( \frac{1.05}{1.19} )}

Divide the numbers:

\frac{1.05}{1.19} = 0.88235 \dots

= \frac{ln ( \frac{15}{2} )}{ln ( 0.88235 \dots )}

\frac{ln ( 2 + \frac{( 5 i )}{( n )} ) \cdot ( 5 )}{( n )}

ln ((0.5 + \frac{0.044315}{2}) \cdot 1.05)

lo g_{8} (5) + \frac{1}{4} lo g_{8} (x)

3 lo g_{10} (1 - x) - 3 lo g_{10} (y)

ln (\frac{x ^{2} - 4}{x ^{2} - 7 x + 12})

What is (ln(15)-ln(2))/(ln(1.05)-ln(1.19)) ?
The solution to (ln(15)-ln(2))/(ln(1.05)-ln(1.19)) is (ln(15/2))/(ln(0.88235…))