What is (8.314*298.15)/(2*96485)ln(1*10^{-7}) ?

The solution to (8.314*298.15)/(2*96485)ln(1*10^{-7}) is (2478.8191)/(192970)-7ln(10)

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simplify (8.314298.15)/(296485)ln(1*10^{-7})

simplify

\frac{8.314 \cdot 298.15}{2 \cdot 96485} ln (1 \cdot 1 0^{- 7})

\frac{2478.8191}{192970} - 7 ln (10)

Decimal Notation

- 16.10525 \dots

Solution steps

\frac{8.314 \cdot 298.15}{2 \cdot 96485} ln (1 \cdot 1 0^{- 7})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

\frac{8.314 \cdot 298.15}{2 \cdot 96485} ln (1 \cdot 1 0^{- 7}) = \frac{8.314 \cdot 298.15}{2 \cdot 96485} ln (1) + \frac{8.314 \cdot 298.15}{2 \cdot 96485} ln (1 0^{- 7})

= \frac{8.314 \cdot 298.15}{2 \cdot 96485} ln (1) + \frac{8.314 \cdot 298.15}{2 \cdot 96485} ln (1 0^{- 7})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (1 0^{- 7}) = - 7 ln (10)

= \frac{8.314 \cdot 298.15}{2 \cdot 96485} ln (1) + \frac{8.314 \cdot 298.15}{2 \cdot 96485} - 7 ln (10)

\frac{8.314 \cdot 298.15}{2 \cdot 96485} ln (1) = 0

\frac{8.314 \cdot 298.15}{2 \cdot 96485} = \frac{2478.8191}{192970}

= 0 + \frac{2478.8191}{192970} - 7 ln (10)

0 + \frac{2478.8191}{192970} - 7 ln (10) = \frac{2478.8191}{192970} - 7 ln (10)

= \frac{2478.8191}{192970} - 7 ln (10)

ln (\frac{19}{12})

ln (3 x^{- 4} y)

ln (5 x)

\frac{17}{3} lo g_{10} (x) - \frac{3}{2} lo g_{10} (y)

lo g_{9} (8)

What is (8.314*298.15)/(2*96485)ln(1*10^{-7}) ?
The solution to (8.314*298.15)/(2*96485)ln(1*10^{-7}) is (2478.8191)/(192970)-7ln(10)