What are the solutions to the equation 0=12x^2-72x+96 ?

The solutions to the equation 0=12x^2-72x+96 are x=4,x=2

Find the zeros of 0=12x^2-72x+96

The zeros of 0=12x^2-72x+96 are x=4,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 12 x^{2} - 72 x + 96

x = 4, x = 2

Solution steps

0 = 12 x^{2} - 72 x + 96

Switch sides

12 x^{2} - 72 x + 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 12 \cdot 96}{2 \cdot 12}

(- 72)^{2} - 4 \cdot 12 \cdot 96 = 24

x_{1, 2} = \frac{- ( - 72 ) \pm 24}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 24}{2 \cdot 12}, x_{2} = \frac{- ( - 72 ) - 24}{2 \cdot 12}

x = \frac{- ( - 72 ) + 24}{2 \cdot 12} : 4

x = \frac{- ( - 72 ) - 24}{2 \cdot 12} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

x^{2} - 36 x + 324 = 0

\frac{5}{4} \cdot 6

(- 81)^{\frac{1}{2}}

2 x^{2} + 5 x + 7 = 0

What are the solutions to the equation 0=12x^2-72x+96 ?
The solutions to the equation 0=12x^2-72x+96 are x=4,x=2
Find the zeros of 0=12x^2-72x+96
The zeros of 0=12x^2-72x+96 are x=4,x=2