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Popular >

simplify ln|x+1|-ln|x-1|

Solution

simplify

ln ∣ x + 1 ∣ - ln ∣ x - 1 ∣

Solution

ln (\frac{∣ x + 1 ∣}{∣ x - 1 ∣})

Solution steps

ln ∣ x + 1 ∣ - ln ∣ x - 1 ∣

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ∣ x + 1 ∣ - ln ∣ x - 1 ∣ = ln (\frac{∣ x + 1 ∣}{∣ x - 1 ∣})

= ln (\frac{∣ x + 1 ∣}{∣ x - 1 ∣})

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Frequently Asked Questions (FAQ)

What is ln|x+1|-ln|x-1| ?
The solution to ln|x+1|-ln|x-1| is ln((|x+1|)/(|x-1|))