What is 120+10log_{10}(1/(4*3.14*100))+10 ?

The solution to 120+10log_{10}(1/(4*3.14*100))+10 is 130-10log_{10}(1256)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 120+10log_{10}(1/(43.14100))+10

simplify

120 + 10 lo g_{10} (\frac{1}{4 \cdot 3.14 \cdot 100}) + 10

130 - 10 lo g_{10} (1256)

Decimal Notation

99.01010 \dots

Solution steps

120 + 10 lo g_{10} (\frac{1}{4 \cdot 3.14 \cdot 100}) + 10

Add the numbers:

120 + 10 = 130

= 130 + 10 lo g_{10} (\frac{1}{4 \cdot 3.14 \cdot 100})

10 lo g_{10} (\frac{1}{4 \cdot 3.14 \cdot 100}) = - 10 lo g_{10} (1256)

= 130 - 10 lo g_{10} (1256)

lo g_{10} (5 x) + lo g_{7} (x)

3 ln (\frac{10 + 104}{2})

\frac{1}{6} ln (d) - 6 ln (f)

4.76 + lo g_{10} (\frac{0.022}{0.1})

ln (x + 1) + ln (x)

What is 120+10log_{10}(1/(4*3.14*100))+10 ?
The solution to 120+10log_{10}(1/(4*3.14*100))+10 is 130-10log_{10}(1256)