What are the solutions to the equation (5x+1)^2=7 ?

The solutions to the equation (5x+1)^2=7 are x=(sqrt(7)-1)/5 ,x=(-sqrt(7)-1)/5

Find the zeros of (5x+1)^2=7

The zeros of (5x+1)^2=7 are x=(sqrt(7)-1)/5 ,x=(-sqrt(7)-1)/5

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(5 x + 1)^{2} = 7

x = \frac{7 - 1}{5}, x = \frac{- 7 - 1}{5}

Decimal Notation

x = 0.32915 \dots, x = - 0.72915 \dots

Solution steps

(5 x + 1)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 1 = 7 : x = \frac{7 - 1}{5}

Solve

5 x + 1 = - 7 : x = \frac{- 7 - 1}{5}

The solutions to the quadratic equation are:

x = \frac{7 - 1}{5}, x = \frac{- 7 - 1}{5}

\frac{0.25}{2 π}

(2 x)^{2} (x)

3.5 (\frac{3 π}{2})

3 x^{2} - 5 x y - 12 y^{2}

2 + \frac{3}{5}

What are the solutions to the equation (5x+1)^2=7 ?
The solutions to the equation (5x+1)^2=7 are x=(sqrt(7)-1)/5 ,x=(-sqrt(7)-1)/5
Find the zeros of (5x+1)^2=7
The zeros of (5x+1)^2=7 are x=(sqrt(7)-1)/5 ,x=(-sqrt(7)-1)/5