What is 20e^9+ln(12)+50-ln(9) ?

The solution to 20e^9+ln(12)+50-ln(9) is 20e^9+ln(4/3)+50

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simplify 20e^9+ln(12)+50-ln(9)

simplify

20 e^{9} + ln (12) + 50 - ln (9)

20 e^{9} + ln (\frac{4}{3}) + 50

Decimal Notation

162111.96623 \dots

Solution steps

20 e^{9} + ln (12) + 50 - ln (9)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (12) - ln (9) = ln (\frac{12}{9})

= 20 e^{9} + ln (\frac{12}{9}) + 50

Cancel the common factor:

3

= 20 e^{9} + ln (\frac{4}{3}) + 50

- lo g_{10} (2.3 \cdot 1 0^{- 9})

ln (\frac{1}{2 ^{n}} \cdot e^{- 2 x} e^{- 3 t})

\frac{3}{2} (lo g_{10} (4.94145) - lo g_{10} (761.21))

ln (\frac{r \cdot 0.04}{2.51})

3 lo g_{5} (a) - 3 lo g_{5} (b)

What is 20e^9+ln(12)+50-ln(9) ?
The solution to 20e^9+ln(12)+50-ln(9) is 20e^9+ln(4/3)+50