What is ln((1.999-2)/(1.999+1)) ?

The solution to ln((1.999-2)/(1.999+1)) is ln(-0.001)-ln(2.999)

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simplify ln((1.999-2)/(1.999+1))

simplify

ln (\frac{1.999 - 2}{1.999 + 1})

ln (- 0.001) - ln (2.999)

Solution steps

ln (\frac{1.999 - 2}{1.999 + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1.999 - 2}{1.999 + 1}) = ln (1.999 - 2) - ln (1.999 + 1)

= ln (1.999 - 2) - ln (1 + 1.999)

Subtract the numbers:

1.999 - 2 = - 0.001

= ln (- 0.001) - ln (1 + 1.999)

Add the numbers:

1.999 + 1 = 2.999

= ln (- 0.001) - ln (2.999)

ln (\frac{( \frac{i}{2} - \frac{1}{2} ) !}{π ( \frac{i}{2} ) !})

ln (a) - 5 ln (b)

ln (3) + ln (8)

- ln (\frac{3}{2})

What is ln((1.999-2)/(1.999+1)) ?
The solution to ln((1.999-2)/(1.999+1)) is ln(-0.001)-ln(2.999)