What is the answer to |4x+3|=(x-1)(x+1)+1 ?

The answer to |4x+3|=(x-1)(x+1)+1 is x=-3\lor x=-1\lor x=2-sqrt(7)\lor x=2+sqrt(7)

Solve for x: |4x+3|=(x-1)(x+1)+1

The solution is x=-3\lor x=-1\lor x=2-sqrt(7)\lor x=2+sqrt(7)

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∣ 4 x + 3 ∣ = (x - 1) (x + 1) + 1

x = - 3 or x = - 1 or x = 2 - 7 or x = 2 + 7

Decimal Notation

x = - 3, x = - 1, x = - 0.64575 \dots, x = 4.64575 \dots

Solution steps

∣ 4 x + 3 ∣ = (x - 1) (x + 1) + 1

Find positive and negative intervals

x < - \frac{3}{4}, x \geq - \frac{3}{4}

Solve the inequality for each interval

(x = - 3 or x = - 1) or (x = 2 - 7 or x = 2 + 7)

x = - 3 or x = - 1 or x = 2 - 7 or x = 2 + 7

5 x^{2} y - 45 y

2 (3 x - 9) = 5 x + 2

4 x - 3 \geq 1

- 6 ∣ x + 2 ∣ = 12

x^{3} + 6 x^{2} + 9 x

What is the answer to |4x+3|=(x-1)(x+1)+1 ?
The answer to |4x+3|=(x-1)(x+1)+1 is x=-3\lor x=-1\lor x=2-sqrt(7)\lor x=2+sqrt(7)
Solve for x: |4x+3|=(x-1)(x+1)+1
The solution is x=-3\lor x=-1\lor x=2-sqrt(7)\lor x=2+sqrt(7)