What is factor ln((x+h)^2+(x+h)+1)-ln(x^2+x+1) ?

The solution to factor ln((x+h)^2+(x+h)+1)-ln(x^2+x+1) is ln(((x+h)^2+x+h+1)/(x^2+x+1))

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factor ln((x+h)^2+(x+h)+1)-ln(x^2+x+1)

factor

ln ((x + h)^{2} + (x + h) + 1) - ln (x^{2} + x + 1)

ln (\frac{( x + h ) ^{2} + x + h + 1}{x ^{2} + x + 1})

Solution steps

ln ((x + h)^{2} + (x + h) + 1) - ln (x^{2} + x + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ((x + h)^{2} + (x + h) + 1) - ln (x^{2} + x + 1) = ln (\frac{x + h + ( x + h ) ^{2} + 1}{x ^{2} + x + 1})

= ln (\frac{( x + h ) ^{2} + + x + h + 1}{x ^{2} + x + 1})

Remove parentheses:

(a) = a

= ln (\frac{( x + h ) ^{2} + x + h + 1}{x ^{2} + x + 1})

ln (\frac{2 \cdot 22.91}{0.01173})

ln (\frac{100}{1435})

ln (e^{x} \cdot (x - 1))

0.78 - \frac{0.0592}{2} lo g_{10} (\frac{0.09}{0.06})

What is factor ln((x+h)^2+(x+h)+1)-ln(x^2+x+1) ?
The solution to factor ln((x+h)^2+(x+h)+1)-ln(x^2+x+1) is ln(((x+h)^2+x+h+1)/(x^2+x+1))