What is 6log_{10}(x)-log_{10}(17) ?

The solution to 6log_{10}(x)-log_{10}(17) is log_{10}((x^6)/(17))

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simplify 6log_{10}(x)-log_{10}(17)

simplify

6 lo g_{10} (x) - lo g_{10} (17)

lo g_{10} (\frac{x ^{6}}{17})

Solution steps

6 lo g_{10} (x) - lo g_{10} (17)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

6 lo g_{10} (x) = lo g_{10} (x^{6})

= lo g_{10} (x^{6}) - lo g_{10} (17)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (x^{6}) - lo g_{10} (17) = lo g_{10} (\frac{x ^{6}}{17})

= lo g_{10} (\frac{x ^{6}}{17})

\frac{1}{0.02} ln (35 (e^{0.01} - e^{- 0.02}))

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ln (\frac{( x + 5 ) ( x + 6 ) ^{6}}{( x + 2 ) ^{2} ( x + 3 ) ^{3}})

What is 6log_{10}(x)-log_{10}(17) ?
The solution to 6log_{10}(x)-log_{10}(17) is log_{10}((x^6)/(17))