What are the solutions to the equation 25r^2+10r+1=0 ?

The solutions to the equation 25r^2+10r+1=0 are r=-1/5

Find the zeros of 25r^2+10r+1=0

The zeros of 25r^2+10r+1=0 are r=-1/5

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25 r^{2} + 10 r + 1 = 0

r = - \frac{1}{5}

Solution steps

25 r^{2} + 10 r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 25 \cdot 1}{2 \cdot 25}

1 0^{2} - 4 \cdot 25 \cdot 1 = 0

r_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 25}

r = \frac{- 10}{2 \cdot 25}

\frac{- 10}{2 \cdot 25} = - \frac{1}{5}

r = - \frac{1}{5}

The solution to the quadratic equation is:

r = - \frac{1}{5}

x^{3} \geq 3 x + 18

49 a^{2} - 64

10 n^{2} - 21 n - 49

4 x^{2} + 3 x + 5 = 0

10 x^{3} + 30 x^{2} + 18 x

What are the solutions to the equation 25r^2+10r+1=0 ?
The solutions to the equation 25r^2+10r+1=0 are r=-1/5
Find the zeros of 25r^2+10r+1=0
The zeros of 25r^2+10r+1=0 are r=-1/5