What is ln(e^x+1)+ln(e^{-x}+1) ?

The solution to ln(e^x+1)+ln(e^{-x}+1) is ln((e^x+1)(e^{-x}+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln(e^x+1)+ln(e^{-x}+1)

simplify

ln (e^{x} + 1) + ln (e^{- x} + 1)

ln ((e^{x} + 1) (e^{- x} + 1))

Solution steps

ln (e^{x} + 1) + ln (e^{- x} + 1)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (e^{x} + 1) + ln (e^{- x} + 1) = ln ((e^{x} + 1) (e^{- x} + 1))

= ln ((e^{x} + 1) (e^{- x} + 1))

ln (\frac{77 \cdot 914555 - 77}{914555 - 77})

ln (x^{2} + 4) + ln (x^{2} + x)

ln (15) - 2 (ln (4) + ln (32))

ln (\frac{5}{4}) \cdot 25

ln (\frac{1}{0.15}) 0.1

What is ln(e^x+1)+ln(e^{-x}+1) ?
The solution to ln(e^x+1)+ln(e^{-x}+1) is ln((e^x+1)(e^{-x}+1))