What is 5log_{b}(x+1)-2log_{b}(y) ?

The solution to 5log_{b}(x+1)-2log_{b}(y) is log_{b}(((x+1)^5)/(y^2))

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simplify 5log_{b}(x+1)-2log_{b}(y)

simplify

5 lo g_{b} (x + 1) - 2 lo g_{b} (y)

lo g_{b} (\frac{( x + 1 ) ^{5}}{y ^{2}})

Solution steps

5 lo g_{b} (x + 1) - 2 lo g_{b} (y)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

5 lo g_{b} (x + 1) = lo g_{b} ((x + 1)^{5})

= lo g_{b} ((x + 1)^{5}) - 2 lo g_{b} (y)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{b} (y) = lo g_{b} (y^{2})

= lo g_{b} ((x + 1)^{5}) - lo g_{b} (y^{2})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{b} ((x + 1)^{5}) - lo g_{b} (y^{2}) = lo g_{b} (\frac{( x + 1 ) ^{5}}{y ^{2}})

= lo g_{b} (\frac{( x + 1 ) ^{5}}{y ^{2}})

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What is 5log_{b}(x+1)-2log_{b}(y) ?
The solution to 5log_{b}(x+1)-2log_{b}(y) is log_{b}(((x+1)^5)/(y^2))