What is the answer to -3-2ix+ix+(x+2)2i=0 ?

The answer to -3-2ix+ix+(x+2)2i=0 is x=-4-3i

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-3-2ix+ix+(x+2)2i=0

- 3 - 2 i x + i x + (x + 2) 2 i = 0

x = - 4 - 3 i

Solution steps

- 3 - 2 i x + i x + (x + 2) \cdot 2 i = 0

Add similar elements:

- 2 i x + i x = - i x

- 3 - i x + 2 i (x + 2) = 0

Move

3

to the right side

- i x + 2 i (x + 2) = 3

Expand

2 i (x + 2) : 2 i x + 4 i

- i x + 2 i x + 4 i = 3

Add similar elements:

- i x + 2 i x = i x

i x + 4 i = 3

Move

4 i

to the right side

i x = 3 - 4 i

Divide both sides by

i

x = - 4 - 3 i

7 (3 x + 1) + 8 (2 x - 3) = 4 (3 x - 1) - 7 (x - 4)

e^{- l n (1 - y)}

\frac{6}{7} x - \frac{1}{4} \leq \frac{11}{14} x - \frac{4}{7}

z^{2} - 14 z + 24

7 (v + 5) = 105

What is the answer to -3-2ix+ix+(x+2)2i=0 ?
The answer to -3-2ix+ix+(x+2)2i=0 is x=-4-3i