What is ((ln(7)-ln(3)))/((1.33-0.926)) ?

The solution to ((ln(7)-ln(3)))/((1.33-0.926)) is (ln(7/3))/(0.404)

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simplify ((ln(7)-ln(3)))/((1.33-0.926))

simplify

\frac{( ln ( 7 ) - ln ( 3 ) )}{( 1.33 - 0.926 )}

\frac{ln ( \frac{7}{3} )}{0.404}

Decimal Notation

2.09727 \dots

Solution steps

\frac{( ln ( 7 ) - ln ( 3 ) )}{( 1.33 - 0.926 )}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (7) - ln (3) = ln (\frac{7}{3})

= \frac{ln ( \frac{7}{3} )}{1.33 - 0.926}

Subtract the numbers:

1.33 - 0.926 = 0.404

= \frac{ln ( \frac{7}{3} )}{0.404}

ln (- 4.007 \cdot 1 0^{- 8})

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What is ((ln(7)-ln(3)))/((1.33-0.926)) ?
The solution to ((ln(7)-ln(3)))/((1.33-0.926)) is (ln(7/3))/(0.404)