What are the solutions to the equation (2w-5)w=33 ?

The solutions to the equation (2w-5)w=33 are w= 11/2 ,w=-3

Find the zeros of (2w-5)w=33

The zeros of (2w-5)w=33 are w= 11/2 ,w=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 w - 5) w = 33

w = \frac{11}{2}, w = - 3

Solution steps

(2 w - 5) w = 33

Expand

(2 w - 5) w : 2 w^{2} - 5 w

2 w^{2} - 5 w = 33

Move

33

to the left side

2 w^{2} - 5 w - 33 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 33 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 33) = 17

w_{1, 2} = \frac{- ( - 5 ) \pm 17}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 17}{2 \cdot 2}, w_{2} = \frac{- ( - 5 ) - 17}{2 \cdot 2}

w = \frac{- ( - 5 ) + 17}{2 \cdot 2} : \frac{11}{2}

w = \frac{- ( - 5 ) - 17}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

w = \frac{11}{2}, w = - 3

x^{- \frac{3}{4}}

- \frac{( - 5 )}{2 ( 1 )}

\frac{x - 1}{x + 1} > 1

25 x^{2} - 49 y^{2}

x + x 2 = 10

What are the solutions to the equation (2w-5)w=33 ?
The solutions to the equation (2w-5)w=33 are w= 11/2 ,w=-3
Find the zeros of (2w-5)w=33
The zeros of (2w-5)w=33 are w= 11/2 ,w=-3