What is log_{2}(ac)-1/4 log_{8}(b) ?

The solution to log_{2}(ac)-1/4 log_{8}(b) is log_{2}(a)+log_{2}(c)-1/4 log_{8}(b)

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simplify log_{2}(ac)-1/4 log_{8}(b)

simplify

lo g_{2} (a c) - \frac{1}{4} lo g_{8} (b)

lo g_{2} (a) + lo g_{2} (c) - \frac{1}{4} lo g_{8} (b)

Solution steps

lo g_{2} (a c) - \frac{1}{4} lo g_{8} (b)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{2} (a c) = lo g_{2} (a) + lo g_{2} (c)

= lo g_{2} (a) + lo g_{2} (c) - \frac{1}{4} lo g_{8} (b)

ln (e^{5} x^{- 2})

lo g_{10} (x^{e} e^{x})

2 + lo g_{10} (\frac{8}{0.1})

0.935 \cdot ln (\frac{39 + 273}{337 + 273})

- ln (6 - 3) + 2 ln (6 - 2)

What is log_{2}(ac)-1/4 log_{8}(b) ?
The solution to log_{2}(ac)-1/4 log_{8}(b) is log_{2}(a)+log_{2}(c)-1/4 log_{8}(b)