What is ln((1-e^x)/(1+e^2)) ?

The solution to ln((1-e^x)/(1+e^2)) is ln(1-e^x)-ln(1+e^2)

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simplify ln((1-e^x)/(1+e^2))

simplify

ln (\frac{1 - e ^{x}}{1 + e ^{2}})

ln (1 - e^{x}) - ln (1 + e^{2})

Solution steps

ln (\frac{1 - e ^{x}}{1 + e ^{2}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1 - e ^{x}}{1 + e ^{2}}) = ln (1 - e^{x}) - ln (1 + e^{2})

= ln (- e^{x} + 1) - ln (e^{2} + 1)

lo g_{3} (\frac{x ^{4}}{y ^{2}})

ln (2 n^{2} + 4 n - 3) - ln (n^{2} + 4 n + 5)

- ln (\frac{2}{3}) + 2

lo g_{2} (\frac{1}{2 \cdot 0.001})

ln (A x^{b} y^{c})

What is ln((1-e^x)/(1+e^2)) ?
The solution to ln((1-e^x)/(1+e^2)) is ln(1-e^x)-ln(1+e^2)