What is 20*log_{10}((x*2pi*628.32)/((10*0.02))) ?

The solution to 20*log_{10}((x*2pi*628.32)/((10*0.02))) is 20(log_{10}(1256.64pix)-log_{10}(0.2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 20log_{10}((x2pi628.32)/((100.02)))

simplify

20 \cdot lo g_{10} (\frac{x \cdot 2 π \cdot 628.32}{( 10 \cdot 0.02 )})

20 (lo g_{10} (1256.64 π x) - lo g_{10} (0.2))

Solution steps

20 lo g_{10} (\frac{x \cdot 2 π 628.32}{( 10 \cdot 0.02 )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{x \cdot 2 π 628.32}{( 10 \cdot 0.02 )}) = lo g_{10} (x \cdot 2 π 628.32) - lo g_{10} ((10 \cdot 0.02))

= 20 (lo g_{10} (2 \cdot 628.32 π x) - lo g_{10} (10 \cdot 0.02))

Multiply the numbers:

2 \cdot 628.32 = 1256.64

= 20 (lo g_{10} (1256.64 π x) - lo g_{10} (10 \cdot 0.02))

Multiply the numbers:

10 \cdot 0.02 = 0.2

= 20 (lo g_{10} (1256.64 π x) - lo g_{10} (0.2))

ln (\frac{x}{x - 8}) + ln (\frac{x + 8}{x})

\frac{1}{6} \cdot ln (\frac{1}{9 ^{3}})

lo g_{10} (z y^{3})

\frac{1}{2} [ln (3) + 4 ln (x) - 2 ln (x - 1)]

\frac{( 0.5 ln ( 28 ) - ln ( 2 ) )}{0.5}

What is 20*log_{10}((x*2pi*628.32)/((10*0.02))) ?
The solution to 20*log_{10}((x*2pi*628.32)/((10*0.02))) is 20(log_{10}(1256.64pix)-log_{10}(0.2))