What is ln((4x^2+3)(2x-1)) ?

The solution to ln((4x^2+3)(2x-1)) is ln(4x^2+3)+ln(2x-1)

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simplify ln((4x^2+3)(2x-1))

simplify

ln ((4 x^{2} + 3) (2 x - 1))

ln (4 x^{2} + 3) + ln (2 x - 1)

Solution steps

ln ((4 x^{2} + 3) (2 x - 1))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln ((4 x^{2} + 3) (2 x - 1)) = ln (4 x^{2} + 3) + ln (2 x - 1)

= ln (4 x^{2} + 3) + ln (2 x - 1)

ln (1) - \frac{1}{8} (ln (\frac{17}{4} + 2) + ln (\frac{17}{4}))

ln (x + 6) + ln (x + 1)

ln (1 + 3 x) - ln (1 - x)

- lo g_{10} (2.645 \cdot 1 0^{- 6})

ln (\frac{( \frac{1000000}{233687} )}{0.1})

What is ln((4x^2+3)(2x-1)) ?
The solution to ln((4x^2+3)(2x-1)) is ln(4x^2+3)+ln(2x-1)