What are the solutions to the equation 6x^2+96x-13=-13 ?

The solutions to the equation 6x^2+96x-13=-13 are x=0,x=-16

Find the zeros of 6x^2+96x-13=-13

The zeros of 6x^2+96x-13=-13 are x=0,x=-16

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6 x^{2} + 96 x - 13 = - 13

x = 0, x = - 16

Solution steps

6 x^{2} + 96 x - 13 = - 13

Move

13

to the left side

6 x^{2} + 96 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

9 6^{2} - 4 \cdot 6 \cdot 0 = 96

x_{1, 2} = \frac{- 96 \pm 96}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 96 + 96}{2 \cdot 6}, x_{2} = \frac{- 96 - 96}{2 \cdot 6}

x = \frac{- 96 + 96}{2 \cdot 6} : 0

x = \frac{- 96 - 96}{2 \cdot 6} : - 16

The solutions to the quadratic equation are:

x = 0, x = - 16

(- \frac{5}{8}) \cdot (\frac{2}{3})

30 \cdot 10

(\frac{3}{5})^{2} = 1

(\frac{6}{7})^{2}

x^{4} + 8 x

What are the solutions to the equation 6x^2+96x-13=-13 ?
The solutions to the equation 6x^2+96x-13=-13 are x=0,x=-16
Find the zeros of 6x^2+96x-13=-13
The zeros of 6x^2+96x-13=-13 are x=0,x=-16