What is 20e^{3(3)}-ln(3+9)+20e^{3(0)}-ln(0+9) ?

The solution to 20e^{3(3)}-ln(3+9)+20e^{3(0)}-ln(0+9) is 20e^9-ln(108)+20

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simplify 20e^{3(3)}-ln(3+9)+20e^{3(0)}-ln(0+9)

simplify

20 e^{3 (3)} - ln (3 + 9) + 20 e^{3 (0)} - ln (0 + 9)

20 e^{9} - ln (108) + 20

Decimal Notation

162076.99642 \dots

Solution steps

20 e^{3 (3)} - ln (3 + 9) + 20 e^{3 (0)} - ln (0 + 9)

Rewrite

- ln (3 + 9) - ln (0 + 9)

- (ln (3 + 9) + ln (0 + 9))

= 20 e^{3 (3)} - (ln (3 + 9) + ln (0 + 9)) + 20 e^{3 (0)}

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (3 + 9) + ln (0 + 9) = ln ((3 + 9) (0 + 9))

= 20 e^{3 \cdot 3} - ln ((3 + 9) (0 + 9)) + 20 e^{3 \cdot 0}

(3 + 9) (0 + 9) = 108

= 20 e^{3 \cdot 3} - ln (108) + 20 e^{3 \cdot 0}

20 e^{3 \cdot 3} = 20 e^{9}

20 e^{3 \cdot 0} = 20

= 20 e^{9} - ln (108) + 20

- lo g_{10} (4.31 \cdot 1 0^{- 5})

ln (\frac{x}{y ^{3}}) - 3 \cdot ln (\frac{1}{y}) + \frac{1}{2} \cdot ln (\frac{1}{x ^{4} y ^{2}})

ln (20) + ln (30)

5 - lo g_{10} (4.3 \cdot 1 0^{- 5})

ln (y + 1) + ln (C)

What is 20e^{3(3)}-ln(3+9)+20e^{3(0)}-ln(0+9) ?
The solution to 20e^{3(3)}-ln(3+9)+20e^{3(0)}-ln(0+9) is 20e^9-ln(108)+20