What is (e^{7/4})/4+ln((e^{7/4})/2) ?

The solution to (e^{7/4})/4+ln((e^{7/4})/2) is (e^{7/4})/4++7/4 ln(e)-ln(2)

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simplify (e^{7/4})/4+ln((e^{7/4})/2)

simplify

\frac{e ^{\frac{7}{4}}}{4} + ln (\frac{e ^{\frac{7}{4}}}{2})

\frac{e ^{\frac{7}{4}}}{4} + + \frac{7}{4} ln (e) - ln (2)

Decimal Notation

2.49550 \dots

Solution steps

\frac{e ^{\frac{7}{4}}}{4} + ln (\frac{e ^{\frac{7}{4}}}{2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{e ^{\frac{7}{4}}}{2}) = ln (e^{\frac{7}{4}}) - ln (2)

= \frac{e ^{\frac{7}{4}}}{4} + + ln (e^{\frac{7}{4}}) - ln (2)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (e^{\frac{7}{4}}) = \frac{7}{4} ln (e)

= \frac{e ^{\frac{7}{4}}}{4} + + \frac{7}{4} ln (e) - ln (2)

0.0259 \cdot ln (\frac{2 \cdot 1 0 ^{16}}{1.5 \cdot 1 0 ^{10}})

\frac{1}{2} ln (2 \cdot 9.5 + 1) + 2 ln (9.5 - 1)

\frac{1}{0.0105} ln (\frac{8000}{5000})

ln (\frac{129}{1.22})

lo g_{7} (a^{2} b^{3} c)

What is (e^{7/4})/4+ln((e^{7/4})/2) ?
The solution to (e^{7/4})/4+ln((e^{7/4})/2) is (e^{7/4})/4++7/4 ln(e)-ln(2)