What is (ln(2.01)-ln(2))/(2.01-2) ?

The solution to (ln(2.01)-ln(2))/(2.01-2) is (ln(1.005))/(0.01)

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simplify (ln(2.01)-ln(2))/(2.01-2)

simplify

\frac{ln ( 2.01 ) - ln ( 2 )}{2.01 - 2}

\frac{ln ( 1.005 )}{0.01}

Decimal Notation

0.49875 \dots

Solution steps

\frac{ln ( 2.01 ) - ln ( 2 )}{2.01 - 2}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (2.01) - ln (2) = ln (\frac{2.01}{2})

= \frac{ln ( \frac{2.01}{2} )}{2.01 - 2}

Divide the numbers:

\frac{2.01}{2} = 1.005

= \frac{ln ( 1.005 )}{2.01 - 2}

Subtract the numbers:

2.01 - 2 = 0.01

= \frac{ln ( 1.005 )}{0.01}

ln (θ^{n} \cdot x^{θ - 1})

4 ln (x) + 6 ln (y)

ln (\frac{0.01}{1})

3.74 + lo g_{10} (\frac{2.4}{0.1})

\frac{ln \frac{y}{x} + 4 - 6 ln \frac{y}{x} - 1}{5} - ln ∣ x ∣

What is (ln(2.01)-ln(2))/(2.01-2) ?
The solution to (ln(2.01)-ln(2))/(2.01-2) is (ln(1.005))/(0.01)