What are the solutions to the equation 2x^2+8x+6=0 ?

The solutions to the equation 2x^2+8x+6=0 are x=-1,x=-3

Find the zeros of 2x^2+8x+6=0

The zeros of 2x^2+8x+6=0 are x=-1,x=-3

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2 x^{2} + 8 x + 6 = 0

x = - 1, x = - 3

Solution steps

2 x^{2} + 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 6 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 2}, x_{2} = \frac{- 8 - 4}{2 \cdot 2}

x = \frac{- 8 + 4}{2 \cdot 2} : - 1

x = \frac{- 8 - 4}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

- 0.9 > - 7.2

4^{x} + 9 (2^{x}) + 18

\frac{10 m - 90}{m - 9}

5 x + 3 \geq 48

8 x^{2} + 13 x - 6

What are the solutions to the equation 2x^2+8x+6=0 ?
The solutions to the equation 2x^2+8x+6=0 are x=-1,x=-3
Find the zeros of 2x^2+8x+6=0
The zeros of 2x^2+8x+6=0 are x=-1,x=-3