What are the solutions to the equation -0.1x^2+0.8x+7=0 ?

The solutions to the equation -0.1x^2+0.8x+7=0 are x=4-sqrt(86),x=4+sqrt(86)

Find the zeros of -0.1x^2+0.8x+7=0

The zeros of -0.1x^2+0.8x+7=0 are x=4-sqrt(86),x=4+sqrt(86)

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- 0.1 x^{2} + 0.8 x + 7 = 0

x = 4 - 86, x = 4 + 86

Solution steps

- 0.1 x^{2} + 0.8 x + 7 = 0

Multiply both sides by

10

- x^{2} + 8 x + 70 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 70}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 70 = 286

x_{1, 2} = \frac{- 8 \pm 2 86}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 86}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2 86}{2 ( - 1 )}

x = \frac{- 8 + 2 86}{2 ( - 1 )} : 4 - 86

x = \frac{- 8 - 2 86}{2 ( - 1 )} : 4 + 86

The solutions to the quadratic equation are:

x = 4 - 86, x = 4 + 86

\frac{12 x ^{3} y ^{4}}{15 x y ^{5}}

- \frac{9}{12} - (- \frac{7}{4})

\frac{x}{4} - 2 = 1

- 5 x + 10 x + 3 = 5 x + 6

x^{2} - 256

What are the solutions to the equation -0.1x^2+0.8x+7=0 ?
The solutions to the equation -0.1x^2+0.8x+7=0 are x=4-sqrt(86),x=4+sqrt(86)
Find the zeros of -0.1x^2+0.8x+7=0
The zeros of -0.1x^2+0.8x+7=0 are x=4-sqrt(86),x=4+sqrt(86)