What is 12(ln|(0)+2|-ln|(0)+3|)+C ?

The solution to 12(ln|(0)+2|-ln|(0)+3|)+C is 12ln(2/3)+C

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simplify 12(ln|(0)+2|-ln|(0)+3|)+C

simplify

12 (ln ∣ (0) + 2 ∣ - ln ∣ (0) + 3 ∣) + C

12 ln (\frac{2}{3}) + C

Solution steps

12 (ln ∣ (0) + 2 ∣ - ln ∣ (0) + 3 ∣) + C

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ∣ (0) + 2 ∣ - ln ∣ (0) + 3 ∣ = ln (\frac{∣ 0 + 2 ∣}{∣ 0 + 3 ∣})

= 12 ln (\frac{∣ 0 + 2 ∣}{∣ 0 + 3 ∣}) + C

\frac{∣ ( 0 ) + 2 ∣}{∣ ( 0 ) + 3 ∣} = \frac{2}{3}

= 12 ln (\frac{2}{3}) + C

ln (\frac{1}{\frac{1}{n}})

ln (\frac{388}{363})

100 + 20 \cdot ln (\frac{65}{65 - 21})

\frac{1}{3} ln (\frac{2}{3})

- lo g_{10} (3.34272 \cdot 1 0^{- 3})

What is 12(ln|(0)+2|-ln|(0)+3|)+C ?
The solution to 12(ln|(0)+2|-ln|(0)+3|)+C is 12ln(2/3)+C