What is -8<= (-3x+1)/4 <= 6 ?

The solution to -8<= (-3x+1)/4 <= 6 is -23/3 <= x<= 11

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-8<= (-3x+1)/4 <= 6

- 8 \leq \frac{- 3 x + 1}{4} \leq 6

- \frac{23}{3} \leq x \leq 11

Interval Notation

[- \frac{23}{3}, 11]

Decimal Notation

- 7.66666 \dots \leq x \leq 11

Solution steps

- 8 \leq \frac{- 3 x + 1}{4} \leq 6

a \leq u \leq b

then

a \leq u and u \leq b

- 8 \leq \frac{- 3 x + 1}{4} and \frac{- 3 x + 1}{4} \leq 6

- 8 \leq \frac{- 3 x + 1}{4} : x \leq 11

\frac{- 3 x + 1}{4} \leq 6 : x \geq - \frac{23}{3}

Combine the intervals

x \leq 11 and x \geq - \frac{23}{3}

Merge Overlapping Intervals

- \frac{23}{3} \leq x \leq 11

4 ∣ 2 w + 3 ∣ - 7 \leq 9

\frac{a}{5} - 18 = 2

\frac{p}{2} - 2 \leq 1

8 x^{2} - 22 x - 21

(x^{4})^{\frac{1}{2}}

What is -8<= (-3x+1)/4 <= 6 ?
The solution to -8<= (-3x+1)/4 <= 6 is -23/3 <= x<= 11