What is 6.1+log_{10}((31)/(0.03*71)) ?

The solution to 6.1+log_{10}((31)/(0.03*71)) is 6.1++log_{10}(31)-(log_{10}(0.03)+log_{10}(71))

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simplify 6.1+log_{10}((31)/(0.03*71))

simplify

6.1 + lo g_{10} (\frac{31}{0.03 \cdot 71})

6.1 + + lo g_{10} (31) - (lo g_{10} (0.03) + lo g_{10} (71))

Decimal Notation

7.26298 \dots

Solution steps

6.1 + lo g_{10} (\frac{31}{0.03 \cdot 71})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{31}{0.03 \cdot 71}) = lo g_{10} (31) - lo g_{10} (0.03 \cdot 71)

= 6.1 + + lo g_{10} (31) - lo g_{10} (71 \cdot 0.03)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (0.03 \cdot 71) = lo g_{10} (0.03) + lo g_{10} (71)

= 6.1 + + lo g_{10} (31) - (lo g_{10} (71) + lo g_{10} (0.03))

\frac{9}{10} ln (30) - \frac{12}{5} ln (40)

0.14 - \frac{0.0591}{2} \cdot lo g_{10} (\frac{1}{3})

ln ((1 + (10)^{2}) \cdot (- 20)^{2})

ln (x) - \frac{1}{4} ln (y)

- lo g_{10} (1.7 (1 0^{- 9}))

What is 6.1+log_{10}((31)/(0.03*71)) ?
The solution to 6.1+log_{10}((31)/(0.03*71)) is 6.1++log_{10}(31)-(log_{10}(0.03)+log_{10}(71))