What are the solutions to the equation y^2+10y=-9 ?

The solutions to the equation y^2+10y=-9 are y=-1,y=-9

Find the zeros of y^2+10y=-9

The zeros of y^2+10y=-9 are y=-1,y=-9

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y^{2} + 10 y = - 9

y = - 1, y = - 9

Solution steps

y^{2} + 10 y = - 9

Move

9

to the left side

y^{2} + 10 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 9 = 8

y_{1, 2} = \frac{- 10 \pm 8}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 10 + 8}{2 \cdot 1}, y_{2} = \frac{- 10 - 8}{2 \cdot 1}

y = \frac{- 10 + 8}{2 \cdot 1} : - 1

y = \frac{- 10 - 8}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

y = - 1, y = - 9

2 x^{2} - 5 x = 1

2 u - 10 = 8

\frac{3 + \frac{a}{b}}{6 - \frac{a}{b}}

\frac{2}{16} = 8

2 x = 4 - x

What are the solutions to the equation y^2+10y=-9 ?
The solutions to the equation y^2+10y=-9 are y=-1,y=-9
Find the zeros of y^2+10y=-9
The zeros of y^2+10y=-9 are y=-1,y=-9