What is x-1+ln((x-2)/(x+2)) ?

The solution to x-1+ln((x-2)/(x+2)) is x-1++ln(x-2)-ln(x+2)

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simplify x-1+ln((x-2)/(x+2))

simplify

x - 1 + ln (\frac{x - 2}{x + 2})

x - 1 + + ln (x - 2) - ln (x + 2)

Solution steps

x - 1 + ln (\frac{x - 2}{x + 2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{x - 2}{x + 2}) = ln (x - 2) - ln (x + 2)

= x - 1 + + ln (x - 2) - ln (x + 2)

lo g_{10} (\frac{2 x}{y ^{3}})

ln (\frac{1}{x 2 π})

4 lo g_{2} (y - 3) - 6 lo g_{2} (y + 9)

ln (- \frac{2}{5} e^{10 t})

lo g_{e} (x^{2}) - lo g_{e} (lo g_{e} (x))

What is x-1+ln((x-2)/(x+2)) ?
The solution to x-1+ln((x-2)/(x+2)) is x-1++ln(x-2)-ln(x+2)