What is log_{10}(3.436+1)-log_{10}(1.718) ?

The solution to log_{10}(3.436+1)-log_{10}(1.718) is log_{10}(2.58207…)

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simplify log_{10}(3.436+1)-log_{10}(1.718)

simplify

lo g_{10} (3.436 + 1) - lo g_{10} (1.718)

lo g_{10} (2.58207 \dots)

Decimal Notation

0.41196 \dots

Solution steps

lo g_{10} (3.436 + 1) - lo g_{10} (1.718)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (3.436 + 1) - lo g_{10} (1.718) = lo g_{10} (\frac{1 + 3.436}{1.718})

= lo g_{10} (\frac{3.436 + 1}{1.718})

\frac{3.436 + 1}{1.718} = 2.58207 \dots

= lo g_{10} (2.58207 \dots)

(0.717) ln (\frac{252}{17})

ln (\frac{2 x}{3}) + \frac{1}{8} ln (\frac{x}{4}) + \frac{3}{8} ln (\frac{3 x}{4})

ln (a e^{- b x})

- 3 ln (x^{2} + 1) - ln (sin (x))

2 \cdot ln (\frac{2}{3})

What is log_{10}(3.436+1)-log_{10}(1.718) ?
The solution to log_{10}(3.436+1)-log_{10}(1.718) is log_{10}(2.58207…)