What is 10*log_{e}((e-1)/e) ?

The solution to 10*log_{e}((e-1)/e) is 10(ln(e-1)-1)

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simplify 10*log_{e}((e-1)/e)

simplify

10 \cdot lo g_{e} (\frac{e - 1}{e})

10 (ln (e - 1) - 1)

Decimal Notation

- 4.58675 \dots

Solution steps

10 lo g_{e} (\frac{e - 1}{e})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{e} (\frac{e - 1}{e}) = lo g_{e} (e - 1) - lo g_{e} (e)

= 10 (lo g_{e} (e - 1) - lo g_{e} (e))

Apply log rule:

lo g_{e} (x) = ln (x)

= 10 (ln (e - 1) - lo g_{e} (e))

Apply log rule:

lo g_{a} (a) = 1

= 10 (ln (e - 1) - 1)

20 lo g_{10} (0.1) + 20 lo g_{10} (2.4) + 92.45

4.89 + lo g_{10} (\frac{0.35}{0.15})

- 20 lo g_{10} (0.1) + 20 lo g_{10} (3)

10 \cdot lo g_{10} (\frac{x ^{7}}{lo g _{10} ( 1 0 ^{- 12} )})

What is 10*log_{e}((e-1)/e) ?
The solution to 10*log_{e}((e-1)/e) is 10(ln(e-1)-1)