What is 4log_{10}(r)-log_{10}(cx) ?

The solution to 4log_{10}(r)-log_{10}(cx) is log_{10}((r^4)/(cx))

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simplify 4log_{10}(r)-log_{10}(cx)

simplify

4 lo g_{10} (r) - lo g_{10} (c x)

lo g_{10} (\frac{r ^{4}}{c x})

Solution steps

4 lo g_{10} (r) - lo g_{10} (c x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{10} (r) = lo g_{10} (r^{4})

= lo g_{10} (r^{4}) - lo g_{10} (c x)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (r^{4}) - lo g_{10} (c x) = lo g_{10} (\frac{r ^{4}}{c x})

= lo g_{10} (\frac{r ^{4}}{c x})

2 lo g_{10} (x - 3) - 3 lo g_{10} (x)

ln (\frac{20 - 7 \cdot 0.0679}{40 - 7 \cdot 0.0679})

lo g_{x} (\frac{1}{3 x})

ln (\frac{3 x ^{2}}{θ} \cdot e^{- \frac{3 x ^{2}}{θ}})

ln (x^{2} - 2 x - 24) - ln (x + 4)

What is 4log_{10}(r)-log_{10}(cx) ?
The solution to 4log_{10}(r)-log_{10}(cx) is log_{10}((r^4)/(cx))