What is (19.15)/(3219*0.02)ln(1/(1-0.9)) ?

The solution to (19.15)/(3219*0.02)ln(1/(1-0.9)) is -(19.15ln(0.1))/(64.38)

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simplify (19.15)/(3219*0.02)ln(1/(1-0.9))

simplify

\frac{19.15}{3219 \cdot 0.02} ln (\frac{1}{1 - 0.9})

- \frac{19.15 ln ( 0.1 )}{64.38}

Decimal Notation

0.68490 \dots

Solution steps

\frac{19.15}{3219 \cdot 0.02} ln (\frac{1}{1 - 0.9})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1}{1 - 0.9}) = ln (1) - ln (1 - 0.9)

= \frac{19.15}{3219 \cdot 0.02} (ln (1) - ln (1 - 0.9))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{19.15 ( ln ( 1 ) - ln ( 1 - 0.9 ) )}{3219 \cdot 0.02}

Subtract the numbers:

1 - 0.9 = 0.1

= \frac{19.15 ( ln ( 1 ) - ln ( 0.1 ) )}{3219 \cdot 0.02}

Multiply the numbers:

3219 \cdot 0.02 = 64.38

= \frac{19.15 ( ln ( 1 ) - ln ( 0.1 ) )}{64.38}

Apply log rule:

lo g_{a} (1) = 0

= \frac{19.15 ( - ln ( 0.1 ) + 0 )}{64.38}

19.15 (0 - ln (0.1)) = - 19.15 ln (0.1)

= \frac{- 19.15 ln ( 0.1 )}{64.38}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{19.15 ln ( 0.1 )}{64.38}

ln (3 x) - x (\frac{1}{x})

- lo g_{10} (2.85 \cdot 1 0^{- 2})

\frac{π}{6} ln (5)

6 lo g_{c} (x) - \frac{1}{2} lo g_{c} (z) + 7 lo g_{c} (w)

ln (\frac{1}{29})

What is (19.15)/(3219*0.02)ln(1/(1-0.9)) ?
The solution to (19.15)/(3219*0.02)ln(1/(1-0.9)) is -(19.15ln(0.1))/(64.38)