What is ln(2n^3+2)-ln(5n^3+2n^2+4) ?

The solution to ln(2n^3+2)-ln(5n^3+2n^2+4) is ln((2n^3+2)/(5n^3+2n^2+4))

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simplify ln(2n^3+2)-ln(5n^3+2n^2+4)

simplify

ln (2 n^{3} + 2) - ln (5 n^{3} + 2 n^{2} + 4)

ln (\frac{2 n ^{3} + 2}{5 n ^{3} + 2 n ^{2} + 4})

Solution steps

ln (2 n^{3} + 2) - ln (5 n^{3} + 2 n^{2} + 4)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (2 n^{3} + 2) - ln (5 n^{3} + 2 n^{2} + 4) = ln (\frac{2 n ^{3} + 2}{5 n ^{3} + 2 n ^{2} + 4})

= ln (\frac{2 n ^{3} + 2}{5 n ^{3} + 2 n ^{2} + 4})

2 ln (t) + ln^{2} (t)

4 - \frac{5}{2} ln (5) - \frac{11}{8} + \frac{5}{2} ln (2)

lo g_{10} (\frac{x ^{2} - 4}{( x + 3 ) ^{2}})

- lo g_{10} (3.46 \cdot 1 0^{- 7})

ln (θ e^{(θ - 1) l n (x)})

What is ln(2n^3+2)-ln(5n^3+2n^2+4) ?
The solution to ln(2n^3+2)-ln(5n^3+2n^2+4) is ln((2n^3+2)/(5n^3+2n^2+4))