What are the solutions to the equation (1+x^2)=0 ?

The solutions to the equation (1+x^2)=0 are x=i,x=-i

Find the zeros of (1+x^2)=0

The zeros of (1+x^2)=0 are x=i,x=-i

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(1 + x^{2}) = 0

x = i, x = - i

Solution steps

(1 + x^{2}) = 0

1 + x^{2} = 0

Move

1

to the right side

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

\frac{x}{6} \leq - 5

3 b^{2} - 4 b - 32

x^{2} + \frac{7}{6} x + \frac{7}{18} = 0

6 = \frac{u}{9.6}

- 6 < x < - 3

What are the solutions to the equation (1+x^2)=0 ?
The solutions to the equation (1+x^2)=0 are x=i,x=-i
Find the zeros of (1+x^2)=0
The zeros of (1+x^2)=0 are x=i,x=-i