What is (ln(ln(3))-ln(ln(2)))dx ?

The solution to (ln(ln(3))-ln(ln(2)))dx is ln((ln(3))/(ln(2)))dx

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simplify (ln(ln(3))-ln(ln(2)))dx

simplify

(ln (ln (3)) - ln (ln (2))) d x

ln (\frac{ln ( 3 )}{ln ( 2 )}) d x

Solution steps

(ln (ln (3)) - ln (ln (2))) d x

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (ln (3)) - ln (ln (2)) = ln (\frac{ln ( 3 )}{ln ( 2 )})

= ln (\frac{ln ( 3 )}{ln ( 2 )}) d x

2 lo g_{3^{^{'}}} (+ 4 lo g_{2^{^{'}}} (- 2 lo g_{1 2^{^{'}}} (x)))

lo g_{7} (5) + 3 lo g_{7} (x) - 6 lo g_{7} (y)

ln (\frac{1}{x} e^{\frac{- y}{x}})

- 10 ln (\frac{91.2 - 70}{98.6 - 70})

- lo g_{10} (7.3 \cdot 1 0^{- 4})

What is (ln(ln(3))-ln(ln(2)))dx ?
The solution to (ln(ln(3))-ln(ln(2)))dx is ln((ln(3))/(ln(2)))dx