What is 2/3*log_{10}(7.71*10^{28})-9.1 ?

The solution to 2/3*log_{10}(7.71*10^{28})-9.1 is 2/3 log_{10}(771)+247/30

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simplify 2/3log_{10}(7.7110^{28})-9.1

simplify

\frac{2}{3} \cdot lo g_{10} (7.71 \cdot 1 0^{28}) - 9.1

\frac{2}{3} lo g_{10} (771) + \frac{247}{30}

Decimal Notation

10.15803 \dots

Solution steps

\frac{2}{3} lo g_{10} (7.71 \cdot 1 0^{28}) - 9.1

9.1 = \frac{91}{10}

= \frac{2}{3} lo g_{10} (7.71 \cdot 1 0^{28}) - \frac{91}{10}

lo g_{10} (7.71 \cdot 1 0^{28}) = lo g_{10} (771) + 26

= \frac{2}{3} (lo g_{10} (771) + 26) - \frac{91}{10}

Expand

\frac{2}{3} (lo g_{10} (771) + 26) - \frac{91}{10} : \frac{2}{3} lo g_{10} (771) + \frac{247}{30}

= \frac{2}{3} lo g_{10} (771) + \frac{247}{30}

- lo g_{10} (8.7 \cdot 1 0^{- 12})

ln (0.61022 \cdot 1 0^{- 5})

14 + lo g_{10} (2.59831 \cdot 1 0^{- 6})

- ln ∣ 2 ∣ - ln \frac{4}{3}

10 (lo g_{10} (\frac{3}{1000}) - lo g_{10} (7.2 E 13 π))

What is 2/3*log_{10}(7.71*10^{28})-9.1 ?
The solution to 2/3*log_{10}(7.71*10^{28})-9.1 is 2/3 log_{10}(771)+247/30