What is ln(x/(x+1))+1/(x+1)+c ?

The solution to ln(x/(x+1))+1/(x+1)+c is ln(x)-ln(x+1)+1/(x+1)+c

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simplify ln(x/(x+1))+1/(x+1)+c

simplify

ln (\frac{x}{x + 1}) + \frac{1}{x + 1} + c

ln (x) - ln (x + 1) + \frac{1}{x + 1} + c

Solution steps

ln (\frac{x}{x + 1}) + \frac{1}{x + 1} + c

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{x}{x + 1}) = ln (x) - ln (x + 1)

= ln (x) - ln (x + 1) + \frac{1}{x + 1} + c

ln (\frac{x + a}{x - a})

2 ln (- 4 ln (x + 2))

ln (\frac{8 x - 2}{x + 2} sin (e^{x}))

- \frac{1}{0.05} ln (\frac{0.6}{8})

\frac{2}{9} ln (3)

What is ln(x/(x+1))+1/(x+1)+c ?
The solution to ln(x/(x+1))+1/(x+1)+c is ln(x)-ln(x+1)+1/(x+1)+c