What is 2log_{10}(tan(10)y^{1/2}) ?

The solution to 2log_{10}(tan(10)y^{1/2}) is 2log_{10}(tan(10))+log_{10}(y)

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simplify 2log_{10}(tan(10)y^{1/2})

simplify

2 lo g_{10} (tan (1 0^{\circ}) y^{\frac{1}{2}})

2 lo g_{10} (tan (1 0^{\circ})) + lo g_{10} (y)

Solution steps

2 lo g_{10} (tan (1 0^{\circ}) y^{\frac{1}{2}})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

2 lo g_{10} (tan (1 0^{\circ}) y^{\frac{1}{2}}) = 2 lo g_{10} (tan (1 0^{\circ})) + 2 lo g_{10} (y^{\frac{1}{2}})

= 2 lo g_{10} (tan (1 0^{\circ})) + 2 lo g_{10} (y^{\frac{1}{2}})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (y^{\frac{1}{2}}) = \frac{1}{2} lo g_{10} (y)

= 2 lo g_{10} (tan (1 0^{\circ})) + 2 \cdot \frac{1}{2} lo g_{10} (y)

2 \cdot \frac{1}{2} lo g_{10} (y) = lo g_{10} (y)

= 2 lo g_{10} (tan (1 0^{\circ})) + lo g_{10} (y)

- lo g_{10} (1.5 x 1 0^{4})

ln (x e^{7 x})

2 ln (2) + 5 ln (x) - \frac{1}{2} ln (x + 3)

\frac{ln ( 2 i ) - ln ( 2 )}{2}

ln (P) - ln (- P + 1)

What is 2log_{10}(tan(10)y^{1/2}) ?
The solution to 2log_{10}(tan(10)y^{1/2}) is 2log_{10}(tan(10))+log_{10}(y)