What is log_{6}(m)+2/3 log_{6}(n) ?

The solution to log_{6}(m)+2/3 log_{6}(n) is log_{6}(mn^{2/3})

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simplify log_{6}(m)+2/3 log_{6}(n)

simplify

lo g_{6} (m) + \frac{2}{3} lo g_{6} (n)

lo g_{6} (m n^{\frac{2}{3}})

Solution steps

lo g_{6} (m) + \frac{2}{3} lo g_{6} (n)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{2}{3} lo g_{6} (n) = lo g_{6} (n^{\frac{2}{3}})

= lo g_{6} (m) + lo g_{6} (n^{\frac{2}{3}})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{6} (m) + lo g_{6} (n^{\frac{2}{3}}) = lo g_{6} (m n^{\frac{2}{3}})

= lo g_{6} (m n^{\frac{2}{3}})

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2 ln ((x + 2)^{2}) - ln (x)

\frac{14 \cdot 0.89}{60 \cdot 0.58} \cdot ln (\frac{1}{1 - 0.1})

2 ln (x^{3} y) + 3 ln (y z^{3})

What is log_{6}(m)+2/3 log_{6}(n) ?
The solution to log_{6}(m)+2/3 log_{6}(n) is log_{6}(mn^{2/3})