What are the solutions to the equation 2(x+1)^2=24 ?

The solutions to the equation 2(x+1)^2=24 are x=2sqrt(3)-1,x=-2sqrt(3)-1

Find the zeros of 2(x+1)^2=24

The zeros of 2(x+1)^2=24 are x=2sqrt(3)-1,x=-2sqrt(3)-1

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2 (x + 1)^{2} = 24

x = 23 - 1, x = - 23 - 1

Decimal Notation

x = 2.46410 \dots, x = - 4.46410 \dots

Solution steps

2 (x + 1)^{2} = 24

Divide both sides by

2

(x + 1)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 12 : x = 23 - 1

Solve

x + 1 = - 12 : x = - 23 - 1

The solutions to the quadratic equation are:

x = 23 - 1, x = - 23 - 1

6 x = 18

x + 8 \leq 12

1^{\frac{7}{3}}

x^{2} + 5 x + \frac{9}{4} = 0

\frac{1}{x + 1} + \frac{1}{x + 2} \geq 0

What are the solutions to the equation 2(x+1)^2=24 ?
The solutions to the equation 2(x+1)^2=24 are x=2sqrt(3)-1,x=-2sqrt(3)-1
Find the zeros of 2(x+1)^2=24
The zeros of 2(x+1)^2=24 are x=2sqrt(3)-1,x=-2sqrt(3)-1