What is join (ln(15))/(2ln(2))-7 ?

The solution to join (ln(15))/(2ln(2))-7 is (ln(15))/(ln(4))-7

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join (ln(15))/(2ln(2))-7

join

\frac{ln ( 15 )}{2 ln ( 2 )} - 7

\frac{ln ( 15 )}{ln ( 4 )} - 7

Decimal Notation

- 5.04655 \dots

Solution steps

\frac{ln ( 15 )}{2 ln ( 2 )} - 7

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (2) = ln (2^{2})

= \frac{ln ( 15 )}{ln ( 2 ^{2} )} - 7

2^{2} = 4

= \frac{ln ( 15 )}{ln ( 4 )} - 7

\frac{1}{10} ln (\frac{11}{15})

ln (7 x + 4) + ln (x + 8)

ln (\frac{5 x}{x - 5})

7 lo g_{b} (x) - \frac{1}{4} lo g_{b} (y) + 5 lo g_{b} (z)

ln (\frac{1}{a ^{2}} x^{n} e^{\frac{b}{a}})

What is join (ln(15))/(2ln(2))-7 ?
The solution to join (ln(15))/(2ln(2))-7 is (ln(15))/(ln(4))-7