What is ln(((6+0))/(4-0)) ?

The solution to ln(((6+0))/(4-0)) is ln(6)-2ln(2)

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simplify ln(((6+0))/(4-0))

simplify

ln (\frac{( 6 + 0 )}{4 - 0})

ln (6) - 2 ln (2)

Decimal Notation

0.40546 \dots

Solution steps

ln (\frac{( 6 + 0 )}{4 - 0})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( 6 + 0 )}{4 - 0}) = ln ((6 + 0)) - ln (4 - 0)

= ln (6 + 0) - ln (4 - 0)

Add the numbers:

6 + 0 = 6

= ln (6) - ln (4 - 0)

Subtract the numbers:

4 - 0 = 4

= ln (6) - ln (4)

ln (4) = 2 ln (2)

= ln (6) - 2 ln (2)

\frac{4 ln ( 2 )}{ln ( \frac{25}{24} )}

lo g_{e} (\frac{1}{4}) + \frac{1}{4}

\frac{d}{d x} (\frac{3}{4 x}) + ln (2 x^{3})

ln (6) - ln (7) - ln (2) + ln (3)

- lo g_{10} (1.89 \cdot 1 0^{- 3})