What is join c*e^{40*(1/20*ln(19/20))=39} ?

The solution to join c*e^{40*(1/20*ln(19/20))=39} is ce^{40ln((19/20)^{1/20})=39}

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join ce^{40(1/20*ln(19/20))=39}

join

c \cdot e^{40 \cdot (\frac{1}{20} \cdot l n (\frac{19}{20})) = 39}

c e^{40 l n ((\frac{19}{20})^{\frac{1}{20}}) = 39}

Solution steps

c e^{40 (\frac{1}{20} l n (\frac{19}{20})) = 39}

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{1}{20} ln (\frac{19}{20}) = ln ((\frac{19}{20})^{\frac{1}{20}})

= e^{40 \cdot 39 l n ((\frac{19}{20})^{\frac{1}{20}}) =} c

3 lo g_{3^{^{'}}} (- 2 lo g_{6} (x))

lo g_{2} (3) + 4 lo g_{2} (x) + \frac{1}{2} lo g_{2} (y)

- lo g_{10} (0.56) - (1 - 1) \cdot lo g_{10} (1 - 0.56)

lo g_{10} (\frac{x ^{4}}{y ^{5} z})

\frac{1}{12} ln ∣ (12 \cdot 5) + 150 ∣ - \frac{1}{12} ln ∣ 12 + 6 ∣

What is join c*e^{40*(1/20*ln(19/20))=39} ?
The solution to join c*e^{40*(1/20*ln(19/20))=39} is ce^{40ln((19/20)^{1/20})=39}