What is expand x^{log_{x}((x+3)^2)=16} ?

The solution to expand x^{log_{x}((x+3)^2)=16} is x^{2log_{x}(x+3)=16}

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expand x^{log_{x}((x+3)^2)=16}

expand

x^{l o g_{x} ((x + 3)^{2}) = 16}

x^{2 l o g_{x} (x + 3) = 16}

Solution steps

x^{l o g_{x} ((x + 3)^{2}) = 16}

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{x} ((x + 3)^{2}) = 2 lo g_{x} (x + 3)

= x^{2 l o g_{x} (x + 3) = 16}

ln (a) + 2 ln (b)

ln (x) - ln (1 - x)

\frac{ln ( \frac{8}{5} )}{2 ln ( 5 )}

- \frac{1}{0.19} ln (\frac{2}{11})

14 - lo g_{10} (1.3 \cdot 1 0^{- 5})

What is expand x^{log_{x}((x+3)^2)=16} ?
The solution to expand x^{log_{x}((x+3)^2)=16} is x^{2log_{x}(x+3)=16}