What are the solutions to the equation 5x^2+200=0 ?

The solutions to the equation 5x^2+200=0 are x=2sqrt(10)i,x=-2sqrt(10)i

Find the zeros of 5x^2+200=0

The zeros of 5x^2+200=0 are x=2sqrt(10)i,x=-2sqrt(10)i

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5 x^{2} + 200 = 0

x = 210 i, x = - 210 i

Solution steps

5 x^{2} + 200 = 0

Move

200

to the right side

5 x^{2} = - 200

Divide both sides by

5

x^{2} = - 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 40, x = - - 40

- 40 = 210 i

- - 40 = - 210 i

x = 210 i, x = - 210 i

x^{3} \geq 11 x^{2}

2 y = 3

5 (1 - x) > 4 (3 - x)

\frac{1}{x + 1} < \frac{1}{x}

p^{2} + 12 p = 0

What are the solutions to the equation 5x^2+200=0 ?
The solutions to the equation 5x^2+200=0 are x=2sqrt(10)i,x=-2sqrt(10)i
Find the zeros of 5x^2+200=0
The zeros of 5x^2+200=0 are x=2sqrt(10)i,x=-2sqrt(10)i