What is 1/2 ln((sin(x)+1)/(sin(x)-1)) ?

The solution to 1/2 ln((sin(x)+1)/(sin(x)-1)) is 1/2 (ln(sin(x)+1)-ln(sin(x)-1))

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simplify 1/2 ln((sin(x)+1)/(sin(x)-1))

simplify

\frac{1}{2} ln (\frac{sin ( x ) + 1}{sin ( x ) - 1})

\frac{1}{2} (ln (sin (x) + 1) - ln (sin (x) - 1))

Solution steps

\frac{1}{2} ln (\frac{sin ( x ) + 1}{sin ( x ) - 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{sin ( x ) + 1}{sin ( x ) - 1}) = ln (sin (x) + 1) - ln (sin (x) - 1)

= \frac{1}{2} (ln (sin (x) + 1) - ln (sin (x) - 1))

ln (\frac{- 1}{0 \cdot 1 - 2})

\frac{6}{5} ln (\frac{y}{x} + 4) - \frac{1}{5} ln (\frac{y}{x} - 1) + ln (x)

\frac{1}{2} ln ∣ x - 3 ∣ + \frac{1}{2} ln ∣ x + 3 ∣ - ln ∣ x ∣

ln (\frac{1}{0.15})

ln (\frac{84}{92})

What is 1/2 ln((sin(x)+1)/(sin(x)-1)) ?
The solution to 1/2 ln((sin(x)+1)/(sin(x)-1)) is 1/2 (ln(sin(x)+1)-ln(sin(x)-1))